Physics - Wave Optics Question with Solution | TestHub

In Young's double slit experiment fringe width $$\beta =\frac{\lambda D}{d}$$ where $D=$ distance between slit and screen $d=$ distance between slit According to the question $D$ is double $\to 2D$ and $d$ is half $\to$ $\frac{d}{2}$ Ther New fringe wilth will be $\frac{\lambda \times 2D}{\frac{d}{2}}=\frac{4\lambda D}{d}=4\left(\frac{\lambda D}{d}\right)=\beta$ ${\beta }^1=4\beta$ i.e., becomes four times