Physics - Wave on String Question with Solution | TestHub

The standard wave equation is $y=A\cos (\omega t-kx)$. Comparing $y=25\cos (2\pi t-\pi x)$ to the standard form, the amplitude $A=25$. The angular frequency $\omega =2\pi$, so the frequency $f=\omega /(2\pi )=2\pi /(2\pi )=1$ Hz.

The final answer is $\boxed{2}$.