A wire of density 7.8 g/cm³, 90 cm between clamps, is extended by 0.03 cm ( Y = 7.8 × 1 0 11 dyne/cm²). Find its lowest transverse frequency. (answer in Hz ).

Strain = 3.33 × 1 0 − 4 , stress = 2.6 × 1 0 8 , v = 2.6 × 1 0 8 /7.8 = 5774 cm/s, f = 5774/180 = 32.1 Hz.

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Physics - Wave on String Question with Solution | TestHub

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A wire of density 7.8 g/cm³, 90 cm between clamps, is extended by 0.03 cm ( $Y = 7.8 \times 1 0^{11}$ dyne/cm²). Find its lowest transverse frequency. (answer in $Hz$ ).

Answer:

32.10

Solution:

Strain = $3.33 \times 1 0^{- 4}$ , stress = $2.6 \times 1 0^{8}$ , $v = 2.6 \times 1 0^{8} /7.8 = 5774$ cm/s, $f = 5774/180 = 32.1$ Hz.

Stream:JEESubject:PhysicsTopic:Wave on StringSubtopic:Waves

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