Physics - Wave on String Question with Solution | TestHub

The given equation of the wave is $Y=0.04\sin (\pi (2t-0.02x))$.

The phase of the wave at position $x$ and time $t$ is $\varphi =2\pi t-0.02\pi x$.

Comparing this with the standard wave equation $Y=A\sin (\omega t-kx)$, the propagation constant is $k=0.02\pi$.

At a given instant of time, the phase difference $\Delta \varphi$ between two particles separated by a distance $\Delta x$ is given by $\Delta \varphi =k\Delta x$.

Given the distance between the particles is $\Delta x=10$ m.

Substituting the values, we get $\Delta \varphi =0.02\pi (10)=0.2\pi =\frac{\pi }{5}$ radian.

Answer: $\frac{\pi }{5}$