Two points are located at a distance of 10 m and 15 m from the source of oscillation. The period of oscillation is 0.05 s and the velocity of the wave is 300 m / s . What is the phase difference betwe

Question

Two points are located at a distance of 10 m and 15 m from the source of oscillation. The period of oscillation is 0.05 s and the velocity of the wave is 300 m / s . What is the phase difference between the oscillations of two points?NEET 2008 (Screening)

TestHub · Accepted Answer

Key Idea : Phase difference = λ 2 π ​ × path difference Path difference between two points, Δ x = 15 − 10 = 5 m Time period, T = 0.05 s ⇒ frequency v = T 1 ​ = 0.05 1 ​ = 20 Hz Velocity, y = 300 m / s ∴ Wavelength, λ = v v ​ = 20 300 ​ = 15 m Hence, phase difference Δ ϕ ​ = λ 2 π ​ × Δ x = 15 2 π ​ × 5 = 3 2 π ​ ​

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