Physics - Wave on String Question with Solution | TestHub

A sonometer wire is fixed at both ends.

For a string fixed at both ends, the $n$-th overtone corresponds to the $(n+1)$-th harmonic, which consists of $n+1$ loops.

For the third overtone, $n=3$.

Number of loops $=3+1=4$.

Since each loop contains exactly one antinode, the number of antinodes is $4$.

The number of nodes on a string fixed at both ends is always one more than the number of antinodes.

Number of nodes $=4+1=5$.

Thus, the number of antinodes and nodes are $4$ and $5$ respectively.

Answer: $4,5$