Physics - Wave on String Question with Solution | TestHub

Given $A=0.2$ m, $v=360$ m/s, and $\lambda =60$ m.

The frequency of the wave is given by $f=\frac{v}{\lambda }=\frac{360}{60}=6$ Hz.

The general equation for a wave travelling in the positive X-direction is $y=A\sin \left[2\pi \left(ft-\frac{x}{\lambda }\right)\right]$.

Substituting the given values, we get $y=0.2\sin \left[2\pi \left(6t-\frac{x}{60}\right)\right]$.

Answer: $y=0.2\sin \left[2\pi \left(6t-\frac{x}{60}\right)\right]$