Physics - Wave on String Question with Solution | TestHub

PhysicsWave on StringWavesEasy2 minQB

PhysicsEasysingle choice

A stationary wave is $y = 3 sin (0.2 π x) cos (50 π t)$ ( $x$ in cm). The distance between a node and the next antinode is:

Answer:

Solution:

$λ = 2 π /0.2 π = 10$ cm. $λ /4 = 2.5$ cm.

Stream:JEESubject:PhysicsTopic:Wave on StringSubtopic:Waves

⏱ 2mℹ️ Source: QB

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