A loaded vertical wire has fundamental frequency 300 Hz. Its temperature rises by 40°C ( α = 1.5 × 1 0 − 5 /°C). By how much does the frequency change, in Hz?

Δ f = − f α θ /2 = − 300 × 1.5 × 1 0 − 5 × 40/2 = − 0.09 Hz.

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A loaded vertical wire has fundamental frequency 300 Hz. Its temperature rises by 40°C ( $α = 1.5 \times 1 0^{- 5}$ /°C). By how much does the frequency change, in Hz?

Answer:

-0.09

Solution:

$Δ f = - f α θ /2 = - 300 \times 1.5 \times 1 0^{- 5} \times 40/2 = - 0.09$ Hz.

Stream:JEESubject:PhysicsTopic:Wave on StringSubtopic:Waves

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