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Physics - Unit & Dimension Question with Solution | TestHub

PhysicsUnit & DimensionMiscellaneousMedium2 minQB

PhysicsMediumsingle choice

In the formula $X = 3 Y Z^{2}, X$ and $Z$ have dimensions of capacitance and magnetic induction respectively. What are the dimensions of $Y$ in MKSQ system? (JEE 1995)

Options:

Answer:

Solution:

$[Y] = \frac{[ X ]}{[ Z ^{2} ]}$
$= \frac{[ M ^{- 1} L ^{- 2} Q ^{2} T ^{2} ]}{[ M ^{2} Q ^{- 2} T ^{- 2} ]}$
$= [M^{- 3} L^{- 2} T^{4} Q^{4}]$ .

Stream:JEESubject:PhysicsTopic:Unit & DimensionSubtopic:Miscellaneous

⏱ 2mℹ️ Source: QB

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