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PhysicsUnit & DimensionMiscellaneousMedium2 minQB

PhysicsMediumsingle choice

If $F = \frac{2 π C r e ^{- k r}}{v ^{2}}$ where F : force, r : distance, v : velocity and C & k are constants, then dimension of C is :-

Answer:

Solution:

The exponential is dimensionless, so $[C] = \frac{[ F ] [ v ^{2} ]}{[ r ]}$ .

$[C] = \frac{( M L T ^{- 2} ) ( L ^{2} T ^{- 2} )}{L} = M L^{2} T^{- 4}$ . Hence (D).

Stream:JEESubject:PhysicsTopic:Unit & DimensionSubtopic:Miscellaneous

⏱ 2mℹ️ Source: QB

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