Physics - Unit & Dimension Question with Solution | TestHub

PhysicsUnit & DimensionMiscellaneousEasy2 minPYQ_2004

PhysicsEasysingle choice

The dimensions of universal gravitational constant are:NEET 2004

Answer:

Solution:

$F \Rightarrow G = \frac{F R ^{2}}{M m} = \frac{GMm}{R ^{2}} = \frac{[ MLT ^{- 2} ] [ L ^{2} ]}{[ M ^{2} ]} = [M^{- 1} L^{3} T^{- 2}]$

Stream:NEETSubject:PhysicsTopic:Unit & DimensionSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2004

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