Match List-I with List-II.

List-I

List-II
(A)
Coefficient of viscosity
(I)
$[{ML}^{2} T^{- 2}]$
(B)
Surface Tension
(II)
$[{ML}^{2} T^{- 1}]$
(C)
Angular momentum
(III)
$[{ML}^{- 1} T^{- 1}]$
(D)
Rotational kinetic energy
(IV)
$[{ML}^{0} T^{- 2}]$

Question

Match List-I with List-II.

	List-I		List-II
(A)	Coefficient of viscosity	(I)	$[{ML}^{2} T^{- 2}]$
(B)	Surface Tension	(II)	$[{ML}^{2} T^{- 1}]$
(C)	Angular momentum	(III)	$[{ML}^{- 1} T^{- 1}]$
(D)	Rotational kinetic energy	(IV)	$[{ML}^{0} T^{- 2}]$

TestHub · Accepted Answer

Viscous force is given by, F = η A d v d y . Hence, MLT - 2 = η L 2 T - 1 ⇒ η = ML - 1 T - 1 Surface tension is given by, S T = F ℓ . Hence, dimension will be = MLT - 2 [ L ] = ML 0 T - 2 Angular momentum, L = m v r = ML 2 T - 1 Rotational kinetic energy, K . E = 1 2 I ω 2 = ML 2 T - 2

Physics - Unit & Dimension Question with Solution | TestHub

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