Physics - Unit & Dimension Question with Solution | TestHub

PhysicsUnit & DimensionMiscellaneousEasy2 minPYQ_2020

PhysicsEasysingle choice

The dimension of $\frac{B^{2}}{2 μ_{0}},$ where $B$ is magnetic filed and $μ_{0}$ is the magnetic permeability of vacuum, is:

Options:

Answer:

Solution:

Energy density in magnetic filed $= \frac{B^{2}}{2 μ_{0}}$
$= \frac{F o r c e \times d i s p l a c e m e n t}{{(d i s p l a c e m e n t)}^{3}} = \frac{M L T^{- 2} . L}{L^{3}} = {M L}^{- 1} T^{- 2}$

Stream:NTA_ABHYASSubject:PhysicsTopic:Unit & DimensionSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

Doubts & Discussion

Loading discussions...