The dimensions of a b , in the equation P = a - t 2 b x , where P is pressure, x is distance and t is time, are

P = a - t 2 b x ⇒ P b x = a - t 2 ⇒ P b x = a = t 2 Or b = t 2 P x = T 2 M L - 1 T - 2 L = M - 1 T 4 ∴ a b = T 2 M - 1 T 4 = M T - 2

Physics - Unit & Dimension Question with Solution | TestHub

PhysicsUnit & DimensionMiscellaneousEasy2 minPYQ_2020

PhysicsEasysingle choice

The dimensions of $\frac{a}{b}$ , in the equation $P = \frac{a - t^{2}}{b x}$ , where $P$ is pressure, $x$ is distance and $t$ is time, are

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Answer:

Solution:

$P = \frac{a - t^{2}}{b x}$

$\Rightarrow P b x = a - t^{2}$

$\Rightarrow [P b x] = [a] = [t^{2}]$

Or $[b] = \frac{[t^{2}]}{[P] [x]} = \frac{[T^{2}]}{[M L^{- 1} T^{- 2}] [L]} = [M^{- 1} T^{4}]$

$∴ [\frac{a}{b}] = \frac{[T^{2}]}{[M^{- 1} T^{4}]} = [M T^{- 2}]$

Stream:NTA_ABHYASSubject:PhysicsTopic:Unit & DimensionSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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