Match List I with List II
List I List II
A. Torque I. $M L^{- 2} T^{- 2}$
B. Stress II. $M L^{2} T^{- 2}$
C. Pressure gradient III. $M L^{- 1} T^{- 1}$
D. Coefficient of
viscosity IV. $M L^{- 1} T^{- 2}$
Choose the correct answer from the options given below :

Question

Match List I with List II

	List I		List II
A.	Torque	I.	$M L^{- 2} T^{- 2}$
B.	Stress	II.	$M L^{2} T^{- 2}$
C.	Pressure gradient	III.	$M L^{- 1} T^{- 1}$
D.	Coefficient of viscosity	IV.	$M L^{- 1} T^{- 2}$

Choose the correct answer from the options given below :

TestHub · Accepted Answer

The dimensions of the quantities are as follows.
$F = M L T^{- 2} r = L v = L T^{- 1} A = L^{2}$
The dimensional form of stress is same as pressure.
Torque $=$ Force $\times$ distance $= {ML}^{2} T^{- 2}$
Stress $= \frac{Force}{Area} = M L^{- 1} T^{- 2}$
Pressure Gradient $= \frac{d p}{d x} = {ML}^{- 2} T^{- 2}$
$η = \frac{F}{6 π r v} = \frac{M L T^{- 2}}{L \cdot {LT}^{- 1}} = {ML}^{- 1} T^{- 1}$

Physics - Unit & Dimension Question with Solution | TestHub

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