Physics - Unit & Dimension Question with Solution | TestHub

Viscous force, $F=6\pi \eta \text{r}\nu$

 $\therefore \eta =\frac{F}{6\pi \text{r}\nu }$  $\left[\eta \right]=\frac{[F]}{\left[\text{r}\right]\left[\nu \right]}$ 

or $\mathit{\left[}\eta \mathit{\right]}\mathit{=}\frac{\mathit{\left[}{\mathit{\text{MLT}}}^{\mathit{-}\mathit{2}}\mathit{\right]}}{\mathit{\left[}\mathit{\text{L}}\mathit{\right]}\mathit{\left[}{\mathit{\text{LT}}}^{\mathit{-}\mathit{1}}\mathit{\right]}}$