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PhysicsUnit & DimensionMiscellaneousEasy2 minPYQ_2022
PhysicsEasysingle choice

An expression of energy density is given byu=αβsinαxkt, whereα, βare constants,xis displacement,kis Boltzmann constant andtis the temperature. The dimensions ofβwill be

Options:

Answer:
D
Solution:

Given that energy density U=αβsinαxkt

As αxkt should be dimensionless, the dimensions of αx and kt should be same.

αx=ktα=ktx

Now,

U=αβ

β=αU=ktxEV=EttxEV

β=L3L=M0L2T0

Stream:JEESubject:PhysicsTopic:Unit & DimensionSubtopic:Miscellaneous
2mℹ️ Source: PYQ_2022

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