A resistor of 10 kΩ having tolerance 10 % is connected in series with another resistor of 20 kΩ having tolerance 20 % . The tolerance of the combination will be approximately

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∆ R s = ∆ R 1 + ∆ R 2 = 10 100 × 10 + 20 100 × 20 kΩ = 5 kΩ ΔR s R s × 100 = 5 30 × 100 = 50 3 = 17 %

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