Physics - Unit & Dimension Question with Solution | TestHub

As we know,$c=\frac{1}{\sqrt{{\mu }_0{\epsilon }_0}}$
$\therefore \mathrm{ }\sqrt{\frac{{\epsilon }_0}{{\mu }_0}}=\sqrt{\frac{{\epsilon }_0^2}{{\mu }_0{\epsilon }_0}}={\epsilon }_{0}c$
$\therefore \left[\sqrt{\frac{{\epsilon }_0}{{\mu }_0}}\right]=$$\left[{\epsilon }_0\right]\left[c\right]=\left[{\mathrm{M}}^{-1}{\mathrm{L}}^{-3}{\mathrm{T}}^4{\mathrm{A}}^2\right]\left[\mathrm{L}{\mathrm{T}}^{-1}\right]$
$=\left[{\mathrm{M}}^{-1}{\mathrm{L}}^{-2}{\mathrm{T}}^3{\mathrm{A}}^2\right]$