Physics - Unit & Dimension Question with Solution | TestHub

$$\begin{array}{rl}\text{ Resistance }& =\frac{\text{ potential difference }}{\text{ current }}\\ & =\frac{{\mathrm{ML}}^2{\mathrm{T}}^{-3}{\mathrm{A}}^{-1}}{\mathrm{A}}=\left[{\mathrm{ML}}^2{\mathrm{T}}^{-3}{\mathrm{A}}^{-2}\right]\end{array}$$