Physics - Unit & Dimension Question with Solution | TestHub

Given, $F=A\sqrt{x}+B{t}^2$ Here, $F=$ force, $x=$ distance and $t=$ time Dimensionally, $F=A\sqrt{x}=B{t}^2$ $\Rightarrow \frac{A}{B}=\frac{t^2}{\sqrt{x}}\Rightarrow \frac{A}{B}=\frac{\left[{\mathrm{T}}^2\right]}{\left[{\mathrm{L}}^{1/2}\right]}=\left[{\mathrm{L}}^{-1/2}{\mathrm{T}}^2\right]$