Physics - Unit & Dimension Question with Solution | TestHub

Resistivity, $\rho =\frac{m}{n{e}^2\tau }$ $\begin{array}{rl}\because [\mathrm{p}]& =\frac{[\mathrm{M}]}{\left[{\mathrm{L}}^{-3}\right][\mathrm{AT}{]}^2[\mathrm{T}]}\\ & =\left[{\mathrm{ML}}^3{\mathrm{A}}^{-2}{\mathrm{T}}^{-3}\right]\end{array}$ So, electrical conductivity $\sigma =\frac{1}{\rho }$ $[\sigma ]=\frac{1}{[\rho ]}=\left[{\mathrm{M}}^{-1}{\mathrm{L}}^{-3}{\mathrm{A}}^2{\mathrm{T}}^3\right]$