Physics - Unit & Dimension Question with Solution | TestHub

$V=K{\left(h\right)}^a{\left(I\right)}^b{\left(G\right)}^c{\left(C\right)}^d$(V is voltage)
We know$\left[h\right]=M{L}^2{T}^{-1}$
$\left[I\right]=A$
$\left[G\right]=M^{-1}{L}^3{T}^{-2}$
$\left[C\right]=L{T}^{-1}$
$\left[V\right]=M{L}^2{T}^{-3}{A}^{-1}$
$M{L}^2{T}^{-3}{A}^{-1}={\left(M{L}^2{T}^{-1}\right)}^a{\left(A\right)}^b{\left(M^{-1}{L}^3{T}^{-2}\right)}^c{\left(L{T}^{-1}\right)}^d$
$M{L}^2{T}^{-3}{A}^{-1}=M^{a-c}{L}^{2a+3c+d}{T}^{-a-2c-d}{A}^b$
$a-c=1\hspace{0.17em}.....\left(1\right)$
$2a+3c+d=2\hspace{0.17em}.....\left(2\right)$
$-a-2c-d=-3\hspace{0.17em}.....\left(3\right)$
$b=-1\hspace{0.17em}\hspace{0.17em}...\left(4\right)$
On solving
$c=-1$
$a=0$
$d=5,\hspace{0.17em}b=-1$
$V=K{\left(h\right)}^0{\left(A\right)}^{-1}{\left(G\right)}^{-1}{\left(C\right)}^5$