Match List I with List II List - I List - II A Surface tension I. kg m - 1 s - 1 B Pressure II. kg m s - 1 C Viscosity III. kg m - 1 s - 2 D Impulse IV. kg s - 2 Choose the correct answer from the opt

Question

Match List I with List II List - I List - II A Surface tension I. kg m - 1 s - 1 B Pressure II. kg m s - 1 C Viscosity III. kg m - 1 s - 2 D Impulse IV. kg s - 2 Choose the correct answer from the options given below:

TestHub · Accepted Answer

(A) Surface tension is related to force and length as $S = \frac{F}{l} = \frac{M L T^{- 2}}{L} = M T^{- 2}$

$= kg s^{- 2}$ (IV)

(B) Pressure is related to force and area as $P = \frac{F}{A}$

$= \frac{M L T^{- 2}}{L^{2}} = kg m^{- 1} s^{- 2}$ (III)

(C) Viscosity in terms of force, area and velocity gradient is given by $η = \frac{F}{A (\frac{d v}{d x})} = \frac{M L T^{- 2}}{L^{2} (\frac{L T^{- 1}}{L})}$

$= M L^{- 1} T^{- 1} = kg m^{- 1} s^{- 1}$ (I)

(D) Impulse is related to force and time of application as $J = \int F dt = M L T^{- 2} \times T$

$= M L T^{- 1} = kg m s^{- 1}$ (II).

So A-(IV), B-(III), C-(I), D-(II)

Physics - Unit & Dimension Question with Solution | TestHub

Options:

Doubts & Discussion

List - I	List - II
A	Surface tension	I.	$kg m^{- 1} s^{- 1}$
B	Pressure	II.	$kg m s^{- 1}$
C	Viscosity	III.	$kg m^{- 1} s^{- 2}$
D	Impulse	IV.	$kg s^{- 2}$