Physics - Unit & Dimension Question with Solution | TestHub

From the formula $G=\frac{F{R}^2}{m_1{m}_2}$ $\begin{array}{rl}& G=\frac{\text{ Dimensions of dimensions of force }F\times \text{ dimension of }(R{)}^2}{\text{ dimensions of mass }M\times \text{ dimension of mass }M}\end{array}$ $=\frac{\left[{\mathrm{MLT}}^{-2}\right]\left[{\mathrm{L}}^2\right]}{[\mathrm{M}][\mathrm{M}]}=\left[{\mathrm{M}}^{-1}{\mathrm{L}}^3{\mathrm{T}}^{-2}\right]$