Check the dimensional correctness of the relation s = u t + 2 1 a t 2 , where s is displacement, u initial velocity, a acceleration and t time.

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Physics - Unit & Dimension Question with Solution | TestHub

PhysicsUnit & DimensionMiscellaneousEasy2 minQB

PhysicsEasysingle choice

Check the dimensional correctness of the relation $s = u t + \frac{1}{2} a t^{2}$ , where $s$ is displacement, $u$ initial velocity, $a$ acceleration and $t$ time.

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Answer:

Solution:

$[u t] = [L T^{- 1}] [T] = [L]$ and
$[a t^{2}] = [L T^{- 2}] [T^{2}] = [L]$ ;
every term has the dimensions of displacement, so the equation is dimensionally correct.

Stream:JEESubject:PhysicsTopic:Unit & DimensionSubtopic:Miscellaneous

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