The fundamental frequency of an air column in a pipe closed at one end is 150 Hz . If the same pipe is open at both the end, the frequencies produces in Hz are

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For a pipe closed at one end, the fundamental frequency is given by $n_{c} = \frac{v}{4 L}$ .

Given $n_{c} = 150$ Hz.

For a pipe open at both ends, the fundamental frequency is given by $n_{o} = \frac{v}{2 L}$ .

$n_{o} = 2 \times (\frac{v}{4 L}) = 2 \times 150 = 300$ Hz.

An open pipe produces all harmonics, so the frequencies produced are integral multiples of the fundamental frequency.

The frequencies are $n_{o}, 2 n_{o}, 3 n_{o}, 4 n_{o}, \dots$

Substituting the value of $n_{o}$ , the frequencies are $300, 600, 900, 1200, \dots$ Hz.

Answer: $300, 600, 900, 1200, \dots\dots$

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