Physics - Sound Wave Question with Solution | TestHub

The fundamental frequency of a pipe open at both ends is given by $n=\frac{v}{2L}$

Given $v=330$ m/s and $L=60$ cm $=0.6$ m

$n=\frac{330}{2\times 0.6}=\frac{330}{1.2}=275$ Hz

The frequency of the $p$-th harmonic is $n_p=p\times n$

Given $n_p=2.2$ kHz $=2200$ Hz

$2200=p\times 275$

$p=\frac{2200}{275}=8$

Thus, the eighth harmonic mode resonates with the source.

Answer: Eighth