Physics - Sound Wave Question with Solution | TestHub

The correct option is (B). Concept: Path difference and phase difference are related by, $\frac{2\pi \mathrm{X}}{\lambda }=\varphi$ where $\mathrm{x}$ is the path difference, $\varphi$ the phase difference and $\lambda$ the wavelength. The velocity of a wave is given by: $v=\lambda f$, where $f$ is the frequency. Combining the above two equations: $f=\frac{\varphi v}{2\pi x}$ Given, $x=0.54\mathrm{m},\varphi =(1.8\pi )$ and $\mathrm{v}=330\mathrm{m}/\mathrm{s}$, therefore, $\mathrm{f}=\frac{(1.8\pi )(330\mathrm{m}/\mathrm{s})}{2\pi (0.54\mathrm{m})}=550\mathrm{Hz}$