When source of sound and observer both are moving towards each other, the observer will hear

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TestHub · Accepted Answer

When the source of sound and the observer move towards each other, the apparent frequency $f^{'}$ heard by the observer is given by $f^{'} = f (\frac{v + v _{o}}{v - v _{s}})$ .

Since $v + v_{o} > v - v_{s}$ , we have $f^{'} > f$ . Thus, the observer hears a higher frequency.

The apparent wavelength $λ^{'}$ of the sound waves in the medium between the source and the observer is determined by the motion of the source and is given by $λ^{'} = \frac{v - v _{s}}{f}$ .

Since $v - v_{s} < v$ , we have $λ^{'} < λ$ . Thus, the apparent wavelength is lower.

Therefore, the observer will perceive a high frequency and a low wavelength.

Answer: high frequency , low wavelength.

Physics - Sound Wave Question with Solution | TestHub

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