Physics - Sound Wave Question with Solution | TestHub

The optical path between any two points is proportional to the time of travel. The distance traversed by light in a medium of refractive index $\mu$ in time $\mathrm{t}$ is given bywhere $v$ is the velocity of light in the medium. The distance traversed by light in a vacuum in this time, $\Delta =ct$ $=c\cdot \frac{d}{v}[$ from equation (1)]This distance is the equivalent distance in vacuum and is called the optical path. Here, the optical path for first ray $={\mu }_1{L}_1$ The optical path for second ray $={\mu }_2{L}_2$ Path difference $={\mu }_1{L}_1-{\mu }_2{L}_2$ Now, phase difference $=\frac{2\pi }{\lambda }\times$ path difference $=\frac{2\pi }{\lambda }\times \left({\mu }_1{L}_1-{\mu }_2{L}_2\right)$