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PhysicsSound WaveBeatsMedium2 minPYQ_2020

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Two sources of sound $S_{1}$ and $S_{2}$ produce sound waves of same frequency $600 H z .$ A listener is moving from source $S_{1}$ towards $S_{2}$ with a constant speed $u_{0} m / s$ and he hears $10 b e a t s / s .$ The velocity of sound is $330 m / s .$ Then, $u_{0}$ equals:

Options:

Answer:

Solution:

Frequency observed from $S_{1} : f_{1} = 660 (\frac{330 - u_{0}}{330 - 0})$
Frequency observed from $S_{2} : f_{2} = 660 (\frac{330 + u_{0}}{330 - 0})$
As $f_{2} - f_{1} = 10$
$660 [\frac{330 + u_{0}}{330 - 0} - \frac{330 - u_{0}}{330 - 0}] = 10$
$2 (2 u_{0}) = 10$
$u_{0} = 2.5 m / s$

Stream:JEESubject:PhysicsTopic:Sound WaveSubtopic:Beats

⏱ 2mℹ️ Source: PYQ_2020

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