Physics - Sound Wave Question with Solution | TestHub

The first overtone for open pipe is ${\mathrm{f}}_{\mathrm{o}}=\frac{2\mathrm{v}}{2l_{\mathrm{o}}}$ The first overtone for closed pipe is ${\mathrm{f}}_{\mathrm{c}}=\frac{3\mathrm{v}}{4l_{\mathrm{c}}}$ Equating the frequencies, $\frac{2\mathrm{v}}{2l_{\mathrm{o}}}=\frac{3\mathrm{v}}{4l_{\mathrm{c}}}$ $\frac{l_{\mathrm{c}}}{l_{\mathrm{o}}}=\frac{3}{4}$