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Physics - Sound Wave Question with Solution | TestHub

PhysicsSound WaveStanding waveMedium2 minPYQ_2009

PhysicsMediumsingle choice

In a resonance pipe the first and second resonances are obtained at depths $22.7 cm$ and $70.2 cm$ respectively. What will be the end correction ?

Options:

Answer:

Solution:

For end correction $x$ , $\frac{l _{2} + x}{l _{1} + x} = \frac{3 λ /4}{λ /4} = 3$ $x = \frac{l _{2} - 3 l _{1}}{2} = \frac{70.2 - 3 \times 22.7}{2} = 1.05 cm$

Stream:MHT_CETSubject:PhysicsTopic:Sound WaveSubtopic:Standing wave

⏱ 2mℹ️ Source: PYQ_2009

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