Physics - Sound Wave Question with Solution | TestHub

Let $d_1$ and $d_2$ be the distances of the person from the two cliffs.

For the first echo, the time taken is $t_1=1$ s.

$2d_1=v\times t_1\Rightarrow d_1=\frac{340\times 1}{2}=170$ m

For the second echo, the time taken is $t_2=3$ s.

$2d_2=v\times t_2\Rightarrow d_2=\frac{340\times 3}{2}=510$ m

The total distance between the two cliffs is $d=d_1+d_2$.

$d=170+510=680$ m

Answer: 680 m