Consider the Doppler effect in two cases. In the first case, an observer moves towards a stationary source of sound with a speed of 50 m / s . In the second case, the observer is at rest and the sourc

Question

Consider the Doppler effect in two cases. In the first case, an observer moves towards a stationary source of sound with a speed of 50 m / s . In the second case, the observer is at rest and the source moves towards the observer with the same speed of 50 m / s . Then the frequency heard by the observer will be [velocity of sound in air = 330 m / s .]

TestHub · Accepted Answer

For observer moving towards a stationary source, n 1 ​ = n 0 ​ [ v v + v L ​ ​ ] For source moving towards a stationary observer, n 2 ​ = n 0 ​ [ v − v s ​ v ​ ] Substituting the values for v , v L ​ and v S ​ in the equations above ​ n 1 ​ = n 0 ​ [ 330 330 + 50 ​ ] = 1.15 n 0 ​ n 2 ​ = n 0 ​ [ 330 − 50 330 ​ ] = 1.17 n 0 ​ ⇒ n 2 ​ > n 1 ​ ​ ∴ The frequency heard will be more in the second case than in the first case.

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