The equation of a wave on a string of linear mass density 0 . 04 kg m - 1 is given by y = 0.02 m sin ⁡ 2 π t 0.04 ( s ) - x 0.50 ( m ) The tension in the string (in N ) is:

From the given equation v = λ T = 0.50 0.04 Now v = T μ ⇒ T = v 2 μ = 12.5 2 × 0.04 = 6.25 N

Physics - Sound Wave Question with Solution | TestHub

PhysicsSound WaveMiscellaneousEasy2 minPYQ_2020

PhysicsEasynumerical

The equation of a wave on a string of linear mass density $0.04 kg m^{- 1}$ is given by
$y = 0.02 (m) \sin [2 π (\frac{t}{0.04 (s)} - \frac{x}{0.50 (m)})]$
The tension in the string (in $N$ ) is:

Answer:

6.25

Solution:

From the given equation $v = \frac{λ}{T} = \frac{0.50}{0.04}$

Now $v = \sqrt{\frac{T}{μ}} \Rightarrow T = v^{2} μ$

$= {(12.5)}^{2} \times 0.04$

$= 6.25 N$

Stream:JEESubject:PhysicsTopic:Sound WaveSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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