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PhysicsSound WaveWavesMedium2 minQB

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A pipe of length 40 cm is open at both ends ( $v = 340$ m s⁻¹). Which harmonic is excited by a 1275 Hz source?

Answer:

Solution:

$f_{n} = n \times 340/0.8 = 425 n$ Hz. $1275 = 3 \times 425$ , so $n = 3$ .

Stream:JEESubject:PhysicsTopic:Sound WaveSubtopic:Waves

⏱ 2mℹ️ Source: QB

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