Physics - Sound Wave Question with Solution | TestHub

PhysicsSound WaveStanding waveMedium2 minPYQ_2005

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A closed orgon pipe and an open orgon pipe are tuned to the same fundamental frequency. What is the ratio of their lengths?

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Answer:

Solution:

Avoiding end correction, the length of the closed organ pipe is $l_{1} = \frac{λ _{1}}{4}$ or $λ_{1} = 4 l_{1}$ The length of open organ pipe is $l_{2} = \frac{λ _{2}}{2}$ or $λ_{2} = 2 l_{2}$ Here, $n_{1} = n_{2}$ So, $\frac{v}{λ _{1}} = \frac{v}{λ _{2}}$ or $\frac{v}{4 l _{1}} = \frac{v}{2 l _{2}}$ Therefore, $l_{1} : l_{2} = 1 : 2$

Stream:JIPMERSubject:PhysicsTopic:Sound WaveSubtopic:Standing wave

⏱ 2mℹ️ Source: PYQ_2005

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