Physics - Sound Wave Question with Solution | TestHub

${\nu }_1=\frac{v}{{\mathrm{\lambda }}_1}=\frac{v}{1.00}\mathrm{ }\mathrm{a}\mathrm{n}\mathrm{d}\mathrm{ }{\mathrm{\nu }}_2=\frac{v}{{\mathrm{\lambda }}_2}=\frac{v}{1.01}$

$\therefore ∆\nu ={\nu }_1-{\nu }_2=v\left[\frac{1}{1.00}-\frac{0}{1.01}\right]=10$

$\mathrm{o}\mathrm{r}\mathrm{ }\mathrm{ }v=\frac{10\times 1\times 1.01}{0.01}=1010\mathrm{ }\mathrm{f}\mathrm{o}\mathrm{r}\mathrm{ }\mathrm{3 }\mathrm{s}$

$\therefore v=336.6\mathrm{ }\mathrm{m }{\mathrm{s}}^{-1}$