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In the given figure time period (in second) of small oscillations is ( $m = 1 kg, k = 5 N / m$ )

Question diagram: In the given figure time period (in second) of small oscilla

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Answer:

Solution:

Ans. 6.28

$E = \frac{1}{2} mv^{2} + \frac{1}{2} m (2 v)^{2} + \frac{1}{2} kx^{2}$ $E = 5 (\frac{1}{2} mv^{2}) + \frac{1}{2} kx^{2}$ $T = 2 π \frac{5 m}{k}$ $T = 2 π \frac{5 \times 1}{5}$ $T = 2 π$

Stream:JEESubject:PhysicsTopic:SHM

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