A pendulum of length 1 m ( g = π 2 ) hangs next to a wall at 3 ∘ on one side. It is released from 5 ∘ on the other side and bounces elastically off the wall. Find the period, in s.

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TestHub · Accepted Answer

ω = π . From 5 ∘ to the mean: T /4 , i.e. π /2 rad of phase. Mean to 3 ∘ : sin ϕ = 3/5 , ϕ = 0.6435 rad. One way = ( π /2 + 0.6435 ) / π s, period = 2 × this = 1.41 s.

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