A simple pendulum of length L is constructed from a point object of mass m suspended by a massless string attached to a fixed pivot point. A small peg is placed a distance 2 L /3 directly below the fi

Question

A simple pendulum of length L is constructed from a point object of mass m suspended by a massless string attached to a fixed pivot point. A small peg is placed a distance $2 L /3$ directly below the fixed pivot point so that the pendulum would swing as shown in the figure below. The mass is displaced 5 degrees from the vertical and released. How long does it take to return to its starting position?

TestHub · Accepted Answer

The period of a simple pendulum is T = 2 π g L ​ ​ . The pendulum swings with length L for half the period and length L /3 for the other half. Thus, the total time is T /2 + T ′ /2 = π g L ​ ​ + π g L /3 ​ ​ = π g L ​ ​ ( 1 + 3 ​ 1 ​ ) .

Physics - SHM Question with Solution | TestHub

Options:

Doubts & Discussion