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PhysicsSHMComplex situation involving others topicEasy2 minQB
PhysicsEasynumerical

Two blocks P and Q of masses 0.3 kg and 0.4 kg respectively are stuck to each other by some weak glue as shown in the figure. They hang together at the end of a spring with a spring constant k=200 N m-1. The block Q suddenly falls free due to failure of glue, then find the maximum kinetic energy of the block P during subsequent motion (in mJ).


Picture 104

Answer:
40.00
Solution:

LetAbe the amplitude, then we have

kA=mg   ⇒A=mgk

A=0.4×g200=2 cm

Motion starts from the lower extreme.

KEmax=12mω2A2=12×0.3×km×A2

=12×0.3×2000.3×21002

=0.04 J

=40 mJ 

Stream:JEESubject:PhysicsTopic:SHMSubtopic:Complex situation involving others topic
⏱ 2mℹ️ Source: QB

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