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PhysicsSHMCalculation of time periodMedium2 minQB

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The second's pendulum is taken from earth to moon, to keep the time period constant

Answer:

Solution:

$g_{moon} = \frac{g _{earth}}{6}$

$T = 2 π l / g$

For constant $T$ , the length scales with $g$ .

$l_{moon} = \frac{l _{earth}}{6}$

Hence the length should be decreased.

Stream:JEESubject:PhysicsTopic:SHMSubtopic:Calculation of time period

⏱ 2mℹ️ Source: QB

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