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Physics - SHM Question with Solution | TestHub

PhysicsSHMSuperposition of SHMEasy2 minQB

PhysicsEasysingle choice

The motion of a particle varies with time according to the relation $y = a \sin ω t + b \cos ω t$

Options:

Answer:

Solution:

$y = a \sin ω t + b \cos ω t$

Let $a = r \cos θ a n d b = r \sin θ$

$y = r \cos θ \sin ω t + r \sin θ \cos ω t$

$= r \sin (ω t + θ)$

$∴ a^{2} + b^{2} = r^{2} (\cos^{2} θ + \sin^{2} θ) = r^{2}$

or $r = \sqrt{a^{2} + b^{2}}$

Stream:JEESubject:PhysicsTopic:SHMSubtopic:Superposition of SHM

⏱ 2mℹ️ Source: QB

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