Physics - SHM Question with Solution | TestHub

The time period of a simple pendulum is$T_1$when its point of suspension is at rest with respect to the ground. When the point of suspension moves vertically upwards according to the law$y=k{t}^2$where$k=1 {\mathrm{ms}}^{-2}$, its new time period is$T_2$, then the value of$\frac{T_1^2}{T_2^2}$is$[$Take$g=10 {\mathrm{ms}}^{-2}]$