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PhysicsSHMKinematicsMedium2 minPYQ_2022
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The equation of a particle executing simple harmonic motion is given byx=sinπt+13 m. Att=1 s, the speed of particle will be (Given:π=3.14)

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Answer:
A
Solution:

Given, x=sinπt+π3

Velocity  v=dxdt=πcosπt+π3

Now, at t=1 sv=πcosπ+π3

 v=-π2=-3.142=-1.57 m s-1v=157 cm s-1

Stream:JEESubject:PhysicsTopic:SHMSubtopic:Kinematics
2mℹ️ Source: PYQ_2022

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