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Physics - SHM Question with Solution | TestHub

PhysicsSHMCalculation of time periodEasy2 minPYQ_2020

PhysicsEasysingle choice

The motion of a particle executing SHM is given by $x = 0.01 \sin 100 π (t + 0.05)$ , where $x$ is in metre and time $t$ is in second. The time period is

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Answer:

Solution:

$x = 0.01 \sin 100 π (t + 0.05)$

$= 0.01 \sin (100 π t + 5 π)$

$∴$ Angular frequency $ω = 100 π = \frac{2 π}{T}$

or $T = \frac{2}{100} = 0.02$ s

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:SHMSubtopic:Calculation of time period

⏱ 2mℹ️ Source: PYQ_2020

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